Medium
You are given a string s
. We want to partition the string into as many parts as possible so that each letter appears in at most one part.
Return a list of integers representing the size of these parts.
Example 1:
Input: s = “ababcbacadefegdehijhklij”
Output: [9,7,8]
Explanation:
The partition is "ababcbaca", "defegde", "hijhklij".
This is a partition so that each letter appears in at most one part.
A partition like "ababcbacadefegde", "hijhklij" is incorrect, because it splits s into less parts.
Example 2:
Input: s = “eccbbbbdec”
Output: [10]
Constraints:
1 <= s.length <= 500
s
consists of lowercase English letters.function partitionLabels(s: string): number[] {
const map = new Map<string, [number, number]>()
for (let i = 0; i < s.length; i++) {
const c = s[i]
if (!map.has(c)) map.set(c, [i, i])
else map.get(c)[1] = i
}
const arr = Array.from(map.values())
arr.sort((v1, v2) => v1[0] - v2[0])
let start = 0,
end = arr[0][1],
result: number[] = []
for (let i = 1; i < arr.length; i++) {
if (arr[i][0] < end) end = Math.max(end, arr[i][1])
else {
result.push(end - start + 1)
start = arr[i][0]
end = arr[i][1]
}
}
result.push(end - start + 1)
return result
}
export { partitionLabels }