Medium
Given the root
of a binary tree, determine if it is a valid binary search tree (BST).
A valid BST is defined as follows:
Example 1:
Input: root = [2,1,3]
Output: true
Example 2:
Input: root = [5,1,4,null,null,3,6]
Output: false
Explanation: The root node’s value is 5 but its right child’s value is 4.
Constraints:
[1, 104]
.-231 <= Node.val <= 231 - 1
import { TreeNode } from '../../com_github_leetcode/treenode'
function dfs(node: TreeNode | null, lowerBound: number, upperBound: number): boolean {
if (!node) return true
if (node.val <= lowerBound) return false
if (node.val >= upperBound) return false
return dfs(node.left, lowerBound, node.val) && dfs(node.right, node.val, upperBound)
}
function isValidBST(root: TreeNode | null): boolean {
return dfs(root, -Infinity, Infinity)
}
export { isValidBST }