Medium
Given an encoded string, return its decoded string.
The encoding rule is: k[encoded_string]
, where the encoded_string
inside the square brackets is being repeated exactly k
times. Note that k
is guaranteed to be a positive integer.
You may assume that the input string is always valid; No extra white spaces, square brackets are well-formed, etc.
Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k
. For example, there won’t be input like 3a
or 2[4]
.
Example 1:
Input: s = “3[a]2[bc]”
Output: “aaabcbc”
Example 2:
Input: s = “3[a2[c]]”
Output: “accaccacc”
Example 3:
Input: s = “2[abc]3[cd]ef”
Output: “abcabccdcdcdef”
Example 4:
Input: s = “abc3[cd]xyz”
Output: “abccdcdcdxyz”
Constraints:
1 <= s.length <= 30
s
consists of lowercase English letters, digits, and square brackets '[]'
.s
is guaranteed to be a valid input.s
are in the range [1, 300]
.class Solution {
private var i = 0
func decodeString(_ s: String) -> String {
var count = 0
var sb = ""
let chars = Array(s)
while i < chars.count {
let c = chars[i]
i += 1
if c.isLetter {
sb.append(c)
} else if c.isNumber {
count = count * 10 + c.wholeNumberValue!
} else if c == "]" {
break
} else if c == "[" {
// sub problem
let repeatString = decodeString(s)
while count > 0 {
sb.append(repeatString)
count -= 1
}
}
}
return sb
}
}