Easy
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
Implement the MinStack
class:
MinStack()
initializes the stack object.void push(int val)
pushes the element val
onto the stack.void pop()
removes the element on the top of the stack.int top()
gets the top element of the stack.int getMin()
retrieves the minimum element in the stack.Example 1:
Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
Output: [null,null,null,null,-3,null,0,-2]
Explanation:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top(); // return 0
minStack.getMin(); // return -2
Constraints:
-231 <= val <= 231 - 1
pop
, top
and getMin
operations will always be called on non-empty stacks.3 * 104
calls will be made to push
, pop
, top
, and getMin
.class MinStack {
private class Node {
var min: Int
var data: Int
var nextNode: Node?
var previousNode: Node?
init(_ min: Int, _ data: Int, _ previousNode: Node?, _ nextNode: Node?) {
self.min = min
self.data = data
self.previousNode = previousNode
self.nextNode = nextNode
}
}
private var currentNode: Node?
init() {}
func push(_ val: Int) {
if currentNode == nil {
currentNode = Node(val, val, nil, nil)
} else {
let newNode = Node(min(currentNode!.min, val), val, currentNode, nil)
currentNode!.nextNode = newNode
currentNode = newNode
}
}
func pop() {
currentNode = currentNode?.previousNode
}
func top() -> Int {
return currentNode!.data
}
func getMin() -> Int {
return currentNode!.min
}
}
/**
* Your MinStack object will be instantiated and called as such:
* let obj = MinStack()
* obj.push(val)
* obj.pop()
* let ret_3: Int = obj.top()
* let ret_4: Int = obj.getMin()
*/