Medium
Given an array of integers temperatures
represents the daily temperatures, return an array answer
such that answer[i]
is the number of days you have to wait after the ith
day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0
instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 105
30 <= temperatures[i] <= 100
object Solution {
def dailyTemperatures(temperatures: Array[Int]): Array[Int] = {
val sol = new Array[Int](temperatures.length)
sol(temperatures.length - 1) = 0
for (i <- (sol.length - 2) to 0 by -1) {
var j = i + 1
while (j < sol.length) {
if (temperatures(i) < temperatures(j)) {
sol(i) = j - i
j = sol.length // exit loop
} else {
if (sol(j) == 0) {
j = sol.length // exit loop
} else {
j += sol(j)
}
}
}
}
sol
}
}