LeetCode-in-All

543. Diameter of Binary Tree

Easy

Given the root of a binary tree, return the length of the diameter of the tree.

The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.

The length of a path between two nodes is represented by the number of edges between them.

Example 1:

Input: root = [1,2,3,4,5]

Output: 3

Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].

Example 2:

Input: root = [1,2]

Output: 1

Constraints:

Solution

import com_github_leetcode.TreeNode

/*
 * Definition for a binary tree node.
 * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {
 *   var value: Int = _value
 *   var left: TreeNode = _left
 *   var right: TreeNode = _right
 * }
 */
object Solution {
    private var diameter: Int = 0

    def diameterOfBinaryTree(root: TreeNode): Int = {
        diameter = 0
        diameterOfBinaryTreeUtil(root)
        diameter
    }

    private def diameterOfBinaryTreeUtil(root: TreeNode): Int = {
        if (root == null) {
            return 0
        }

        val leftLength = if (root.left != null) 1 + diameterOfBinaryTreeUtil(root.left) else 0
        val rightLength = if (root.right != null) 1 + diameterOfBinaryTreeUtil(root.right) else 0

        diameter = Math.max(diameter, leftLength + rightLength)
        Math.max(leftLength, rightLength)
    }
}