Medium
Given an integer array nums
and an integer k
, return the kth
largest element in the array.
Note that it is the kth
largest element in the sorted order, not the kth
distinct element.
Example 1:
Input: nums = [3,2,1,5,6,4], k = 2
Output: 5
Example 2:
Input: nums = [3,2,3,1,2,4,5,5,6], k = 4
Output: 4
Constraints:
1 <= k <= nums.length <= 104
-104 <= nums[i] <= 104
import scala.util.Sorting
object Solution {
def findKthLargest(nums: Array[Int], k: Int): Int = {
val n = nums.length
Sorting.quickSort(nums)
nums(n - k)
}
}