Medium
There are a total of numCourses
courses you have to take, labeled from 0
to numCourses - 1
. You are given an array prerequisites
where prerequisites[i] = [ai, bi]
indicates that you must take course bi
first if you want to take course ai
.
[0, 1]
, indicates that to take course 0
you have to first take course 1
.Return true
if you can finish all courses. Otherwise, return false
.
Example 1:
Input: numCourses = 2, prerequisites = [[1,0]]
Output: true
Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0. So it is possible.
Example 2:
Input: numCourses = 2, prerequisites = [[1,0],[0,1]]
Output: false
Explanation: There are a total of 2 courses to take. To take course 1 you should have finished course 0, and to take course 0 you should also have finished course 1. So it is impossible.
Constraints:
1 <= numCourses <= 105
0 <= prerequisites.length <= 5000
prerequisites[i].length == 2
0 <= ai, bi < numCourses
object Solution {
def canFinish(numCourses: Int, prerequisites: Array[Array[Int]]): Boolean = {
import scala.collection.mutable.{Queue, ListBuffer}
val indegree = Array.fill(numCourses)(0)
val graph = Array.fill(numCourses)(new ListBuffer[Int])
for (data <- prerequisites) {
val course = data.head
val prerequisiteCourse = data.last
indegree(course) = indegree(course) + 1
graph(prerequisiteCourse) += course
}
val startingCourses = indegree.zipWithIndex.filter(_._1.equals(0)).map(_._2)
val queue = Queue[Int](startingCourses: _*)
var courseTaken = 0
while (queue.nonEmpty) {
val current = queue.dequeue
courseTaken = courseTaken + 1
for (neighbor <- graph(current)) {
indegree(neighbor) = indegree(neighbor) - 1
if (indegree(neighbor).equals(0)) {
queue.enqueue(neighbor)
}
}
}
courseTaken == numCourses
}
}