Medium
Given a string s
, return the number of palindromic substrings in it.
A string is a palindrome when it reads the same backward as forward.
A substring is a contiguous sequence of characters within the string.
Example 1:
Input: s = “abc”
Output: 3
Explanation: Three palindromic strings: “a”, “b”, “c”.
Example 2:
Input: s = “aaa”
Output: 6
Explanation: Six palindromic strings: “a”, “a”, “a”, “aa”, “aa”, “aaa”.
Constraints:
1 <= s.length <= 1000
s
consists of lowercase English letters.impl Solution {
fn expand(s: &[char], mut l: i32, mut r: i32, res: &mut i32) {
while l >= 0 && (r as usize) < s.len() {
if s[l as usize] != s[r as usize] {
return;
} else {
*res += 1;
l -= 1;
r += 1;
}
}
}
pub fn count_substrings(s: String) -> i32 {
let a: Vec<char> = s.chars().collect();
let mut res = 0;
for i in 0..a.len() {
Solution::expand(&a, i as i32, i as i32, &mut res); // Odd length palindromes
Solution::expand(&a, i as i32, (i + 1) as i32, &mut res); // Even length palindromes
}
res
}
}