Medium
Given an array of integers temperatures
represents the daily temperatures, return an array answer
such that answer[i]
is the number of days you have to wait after the ith
day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0
instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 105
30 <= temperatures[i] <= 100
# @param {Integer[]} temperatures
# @return {Integer[]}
def daily_temperatures(temperatures)
sol = Array.new(temperatures.length, 0)
(temperatures.length - 2).downto(0) do |i|
j = i + 1
while j <= temperatures.length
if temperatures[i] < temperatures[j]
sol[i] = j - i
break
else
break if sol[j].zero?
j += sol[j]
end
end
end
sol
end