Medium
Given an encoded string, return its decoded string.
The encoding rule is: k[encoded_string]
, where the encoded_string
inside the square brackets is being repeated exactly k
times. Note that k
is guaranteed to be a positive integer.
You may assume that the input string is always valid; No extra white spaces, square brackets are well-formed, etc.
Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k
. For example, there won’t be input like 3a
or 2[4]
.
Example 1:
Input: s = “3[a]2[bc]”
Output: “aaabcbc”
Example 2:
Input: s = “3[a2[c]]”
Output: “accaccacc”
Example 3:
Input: s = “2[abc]3[cd]ef”
Output: “abcabccdcdcdef”
Example 4:
Input: s = “abc3[cd]xyz”
Output: “abccdcdcdxyz”
Constraints:
1 <= s.length <= 30
s
consists of lowercase English letters, digits, and square brackets '[]'
.s
is guaranteed to be a valid input.s
are in the range [1, 300]
.# @param {String} s
# @return {String}
def decode_string(s)
@i = 0
decode_helper(s)
end
private
def decode_helper(s)
count = 0
result = ""
while @i < s.length
c = s[@i]
@i += 1
if letter?(c)
result += c
elsif digit?(c)
count = count * 10 + c.to_i
elsif c == ']'
break
elsif c == '['
# sub problem
repeat = decode_helper(s)
result += repeat * count
count = 0
end
end
result
end
def letter?(c)
c =~ /[a-zA-Z]/
end
def digit?(c)
c =~ /\d/
end