Medium
Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.
There is only one repeated number in nums, return this repeated number.
You must solve the problem without modifying the array nums and uses only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2]
Output: 2
Example 2:
Input: nums = [3,1,3,4,2]
Output: 3
Example 3:
Input: nums = [1,1]
Output: 1
Example 4:
Input: nums = [1,1,2]
Output: 1
Constraints:
1 <= n <= 105nums.length == n + 11 <= nums[i] <= nnums appear only once except for precisely one integer which appears two or more times.Follow up:
nums?# @param {Integer[]} nums
# @return {Integer}
def find_duplicate(nums)
  arr = Array.new(nums.length + 1, 0)
  nums.each do |num|
    arr[num] += 1
    return num if arr[num] == 2
  end
  0
end