Easy
Given an integer array nums
, move all 0
’s to the end of it while maintaining the relative order of the non-zero elements.
Note that you must do this in-place without making a copy of the array.
Example 1:
Input: nums = [0,1,0,3,12]
Output: [1,3,12,0,0]
Example 2:
Input: nums = [0]
Output: [0]
Constraints:
1 <= nums.length <= 104
-231 <= nums[i] <= 231 - 1
Follow up: Could you minimize the total number of operations done?
# @param {Integer[]} nums
# @return {Void} Do not return anything, modify nums in-place instead.
def move_zeroes(nums)
first_zero = 0
(0...nums.length).each do |i|
if nums[i] != 0
swap(first_zero, i, nums)
first_zero += 1
end
end
end
private
def swap(index1, index2, numbers)
val2 = numbers[index2]
numbers[index2] = numbers[index1]
numbers[index1] = val2
end