Hard
You are given an array of integers nums
, there is a sliding window of size k
which is moving from the very left of the array to the very right. You can only see the k
numbers in the window. Each time the sliding window moves right by one position.
Return the max sliding window.
Example 1:
Input: nums = [1,3,-1,-3,5,3,6,7], k = 3
Output: [3,3,5,5,6,7]
Explanation:
Window position Max
--------------- -----
[1 3 -1] -3 5 3 6 7 3
1 [3 -1 -3] 5 3 6 7 3
1 3 [-1 -3 5] 3 6 7 5
1 3 -1 [-3 5 3] 6 7 5
1 3 -1 -3 [5 3 6] 7 6
1 3 -1 -3 5 [3 6 7] 7
Example 2:
Input: nums = [1], k = 1
Output: [1]
Example 3:
Input: nums = [1,-1], k = 1
Output: [1,-1]
Example 4:
Input: nums = [9,11], k = 2
Output: [11]
Example 5:
Input: nums = [4,-2], k = 2
Output: [4]
Constraints:
1 <= nums.length <= 105
-104 <= nums[i] <= 104
1 <= k <= nums.length
# @param {Integer[]} nums
# @param {Integer} k
# @return {Integer[]}
def max_sliding_window(nums, k)
n = nums.length
res = []
x = 0
dq = []
i = 0
j = 0
while j < n
while !dq.empty? && dq.last < nums[j]
dq.pop
end
dq.push(nums[j])
if j - i + 1 == k
res[x] = dq.first
x += 1
if dq.first == nums[i]
dq.shift
end
i += 1
end
j += 1
end
res
end