Medium
Given an integer array nums
and an integer k
, return the k
most frequent elements. You may return the answer in any order.
Example 1:
Input: nums = [1,1,1,2,2,3], k = 2
Output: [1,2]
Example 2:
Input: nums = [1], k = 1
Output: [1]
Constraints:
1 <= nums.length <= 105
-104 <= nums[i] <= 104
k
is in the range [1, the number of unique elements in the array]
.Follow up: Your algorithm’s time complexity must be better than O(n log n)
, where n is the array’s size.
(define (hash-table-counter ls)
(let ([counts (make-hash)])
(for-each (λ (v) (hash-update! counts v add1 0)) ls)
counts))
(define (top-k-frequent nums k)
(let ([counter (hash-table-counter nums)])
(map car (take (sort (hash->list counter) #:key cdr >) k))))