Medium
Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.
There is only one repeated number in nums, return this repeated number.
You must solve the problem without modifying the array nums and uses only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2]
Output: 2
Example 2:
Input: nums = [3,1,3,4,2]
Output: 3
Constraints:
1 <= n <= 105nums.length == n + 11 <= nums[i] <= nnums appear only once except for precisely one integer which appears two or more times.Follow up:
nums?(require racket/hash)
(define/contract (find-duplicate nums)
  (-> (listof exact-integer?) exact-integer?)
  (letrec
      ([find-recurse
           (lambda (ns seen)
             (cond [(null? ns) -1]
                   [(hash-has-key? seen (car ns)) (car ns)]
                   [else (find-recurse
                           (cdr ns)
                           (hash-union
                             seen
                             (make-immutable-hash (list (cons (car ns) #t)))))]))])
    (find-recurse nums (make-immutable-hash))))