Medium
Given an array of integers nums
containing n + 1
integers where each integer is in the range [1, n]
inclusive.
There is only one repeated number in nums
, return this repeated number.
You must solve the problem without modifying the array nums
and uses only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2]
Output: 2
Example 2:
Input: nums = [3,1,3,4,2]
Output: 3
Constraints:
1 <= n <= 105
nums.length == n + 1
1 <= nums[i] <= n
nums
appear only once except for precisely one integer which appears two or more times.Follow up:
nums
?(require racket/hash)
(define/contract (find-duplicate nums)
(-> (listof exact-integer?) exact-integer?)
(letrec
([find-recurse
(lambda (ns seen)
(cond [(null? ns) -1]
[(hash-has-key? seen (car ns)) (car ns)]
[else (find-recurse
(cdr ns)
(hash-union
seen
(make-immutable-hash (list (cons (car ns) #t)))))]))])
(find-recurse nums (make-immutable-hash))))