Easy
Design a stack that supports push, pop, top, and retrieving the minimum element in constant time.
Implement the MinStack
class:
MinStack()
initializes the stack object.void push(int val)
pushes the element val
onto the stack.void pop()
removes the element on the top of the stack.int top()
gets the top element of the stack.int getMin()
retrieves the minimum element in the stack.Example 1:
Input
["MinStack","push","push","push","getMin","pop","top","getMin"]
[[],[-2],[0],[-3],[],[],[],[]]
Output: [null,null,null,null,-3,null,0,-2]
Explanation:
MinStack minStack = new MinStack();
minStack.push(-2);
minStack.push(0);
minStack.push(-3);
minStack.getMin(); // return -3
minStack.pop();
minStack.top(); // return 0
minStack.getMin(); // return -2
Constraints:
-231 <= val <= 231 - 1
pop
, top
and getMin
operations will always be called on non-empty stacks.3 * 104
calls will be made to push
, pop
, top
, and getMin
.(define min-stack%
(class object%
(super-new)
(define vals '())
; push : exact-integer? -> void?
(define/public (push val)
(let* ([cur-min (if (empty? vals) val (get-min))]
[new-top (cons val (min cur-min val))])
(set! vals (cons new-top vals))))
; pop : -> void?
(define/public (pop)
(define res (top))
(set! vals (cdr vals))
res)
; top : -> exact-integer?
(define/public (top)
(car (first vals)))
; get-min : -> exact-integer?
(define/public (get-min)
(cdr (first vals)))))
;; Your min-stack% object will be instantiated and called as such:
;; (define obj (new min-stack%))
;; (send obj push val)
;; (send obj pop)
;; (define param_3 (send obj top))
;; (define param_4 (send obj get-min))