Medium
Given the head
of a linked list, return the list after sorting it in ascending order.
Example 1:
Input: head = [4,2,1,3]
Output: [1,2,3,4]
Example 2:
Input: head = [-1,5,3,4,0]
Output: [-1,0,3,4,5]
Example 3:
Input: head = []
Output: []
Constraints:
[0, 5 * 104]
.-105 <= Node.val <= 105
Follow up: Can you sort the linked list in O(n logn)
time and O(1)
memory (i.e. constant space)?
; Definition for singly-linked list:
#|
; val : integer?
; next : (or/c list-node? #f)
(struct list-node
(val next) #:mutable #:transparent)
; constructor
(define (make-list-node [val 0])
(list-node val #f))
|#
; Helper function to split the list into two halves
(define (split-list head)
(let loop ([slow head]
[fast head]
[pre #f])
(cond
[(or (not fast) (not (list-node-next fast)))
(when pre
(set-list-node-next! pre #f))
slow]
[else
(loop (list-node-next slow)
(list-node-next (list-node-next fast))
slow)])))
; Helper function to merge two sorted lists
(define (merge-lists l1 l2)
(let ([dummy (list-node 1 #f)])
(let loop ([curr dummy]
[first l1]
[second l2])
(cond
[(not first)
(set-list-node-next! curr second)]
[(not second)
(set-list-node-next! curr first)]
[else
(if (<= (list-node-val first) (list-node-val second))
(begin
(set-list-node-next! curr first)
(loop first (list-node-next first) second))
(begin
(set-list-node-next! curr second)
(loop second first (list-node-next second))))])
(list-node-next dummy))))
; Main sort-list function with contract
(define/contract (sort-list head)
(-> (or/c list-node? #f) (or/c list-node? #f))
(cond
[(or (not head) (not (list-node-next head)))
head]
[else
(let* ([middle (split-list head)]
[first (sort-list head)]
[second (sort-list middle)])
(merge-lists first second))]))