Medium
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = “PAYPALISHIRING”, numRows = 3
Output: “PAHNAPLSIIGYIR”
Example 2:
Input: s = “PAYPALISHIRING”, numRows = 4
Output: “PINALSIGYAHRPI”
Explanation: P I N A L S I G Y A H R P I
Example 3:
Input: s = “A”, numRows = 1
Output: “A”
Constraints:
1 <= s.length <= 1000s consists of English letters (lower-case and upper-case), ',' and '.'.1 <= numRows <= 1000(define/contract (convert s numRows)
  (-> string? exact-integer? string?)
  (let* ((sLen (string-length s))
         (maxDist (- (* numRows 2) 2)))
    (if (= numRows 1)
        s
        (let ((buf ""))
          (for ([i (in-range numRows)])
            (let loop ((index i))
              (when (< index sLen)
                (set! buf (string-append buf (string (string-ref s index))))
                (let ((next-step (- maxDist (* i 2))))
                  (when (and (> i 0) (< i (- numRows 1)) (< (+ index next-step) sLen))
                    (set! buf (string-append buf (string (string-ref s (+ index next-step))))))
                  (loop (+ index maxDist))))))
          buf))))