Medium
Given an array of integers temperatures
represents the daily temperatures, return an array answer
such that answer[i]
is the number of days you have to wait after the ith
day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0
instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 105
30 <= temperatures[i] <= 100
class Solution:
def dailyTemperatures(self, temperatures: List[int]) -> List[int]:
sol = [0] * len(temperatures)
for i in range(len(temperatures) - 2, -1, -1):
j = i + 1
while j < len(temperatures):
if temperatures[i] < temperatures[j]:
sol[i] = j - i
break
elif sol[j] == 0:
break
else:
j += sol[j]
return sol