Medium
Given an array of integers nums
and an integer k
, return the total number of continuous subarrays whose sum equals to k
.
Example 1:
Input: nums = [1,1,1], k = 2
Output: 2
Example 2:
Input: nums = [1,2,3], k = 3
Output: 2
Constraints:
1 <= nums.length <= 2 * 104
-1000 <= nums[i] <= 1000
-107 <= k <= 107
from collections import defaultdict
class Solution:
def subarraySum(self, nums: List[int], k: int) -> int:
tempSum = 0
ret = 0
sumCount = defaultdict(int)
sumCount[0] = 1
for i in nums:
tempSum += i
if tempSum - k in sumCount:
ret += sumCount[tempSum - k]
sumCount[tempSum] += 1
return ret