Medium
You are given an integer array nums
and an integer target
.
You want to build an expression out of nums by adding one of the symbols '+'
and '-'
before each integer in nums and then concatenate all the integers.
nums = [2, 1]
, you can add a '+'
before 2
and a '-'
before 1
and concatenate them to build the expression "+2-1"
.Return the number of different expressions that you can build, which evaluates to target
.
Example 1:
Input: nums = [1,1,1,1,1], target = 3
Output: 5
Explanation:
There are 5 ways to assign symbols to make the sum of nums be target 3.
-1 + 1 + 1 + 1 + 1 = 3
+1 - 1 + 1 + 1 + 1 = 3
+1 + 1 - 1 + 1 + 1 = 3
+1 + 1 + 1 - 1 + 1 = 3
+1 + 1 + 1 + 1 - 1 = 3
Example 2:
Input: nums = [1], target = 1
Output: 1
Constraints:
1 <= nums.length <= 20
0 <= nums[i] <= 1000
0 <= sum(nums[i]) <= 1000
-1000 <= target <= 1000
class Solution {
/**
* @param Integer[] $nums
* @param Integer $target
* @return Integer
*/
public function findTargetSumWays($nums, $s) {
$sum = 0;
$s = abs($s);
foreach ($nums as $num) {
$sum += $num;
}
// Invalid s, just return 0
if ($s > $sum || ($sum + $s) % 2 != 0) {
return 0;
}
$dp = array_fill(0, ($sum + $s) / 2 + 1, array_fill(0, count($nums) + 1, 0));
$dp[0][0] = 1;
// empty knapsack must be processed specially
for ($i = 0; $i < count($nums); $i++) {
if ($nums[$i] == 0) {
$dp[0][$i + 1] = $dp[0][$i] * 2;
} else {
$dp[0][$i + 1] = $dp[0][$i];
}
}
for ($i = 1; $i < count($dp); $i++) {
for ($j = 0; $j < count($nums); $j++) {
$dp[$i][$j + 1] += $dp[$i][$j];
if ($nums[$j] <= $i) {
$dp[$i][$j + 1] += $dp[$i - $nums[$j]][$j];
}
}
}
return $dp[($sum + $s) / 2][count($nums)];
}
}