Medium
Given the root
of a binary tree and an integer targetSum
, return the number of paths where the sum of the values along the path equals targetSum
.
The path does not need to start or end at the root or a leaf, but it must go downwards (i.e., traveling only from parent nodes to child nodes).
Example 1:
Input: root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8
Output: 3
Explanation: The paths that sum to 8 are shown.
Example 2:
Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22
Output: 3
Constraints:
[0, 1000]
.-109 <= Node.val <= 109
-1000 <= targetSum <= 1000
/**
* Definition for a binary tree node.
* class TreeNode {
* public $val = null;
* public $left = null;
* public $right = null;
* function __construct($val = 0, $left = null, $right = null) {
* $this->val = $val;
* $this->left = $left;
* $this->right = $right;
* }
* }
*/
class Solution {
private function countPaths($node, &$count, $prefixSum, $targetSum) {
if ($node === null) {
return 0;
}
if (isset($count[$prefixSum])) {
$count[$prefixSum]++;
} else {
$count[$prefixSum] = 1;
}
$prefixSum += $node->val;
$countValue = 0;
if (isset($count[$prefixSum - $targetSum])) {
$countValue = $count[$prefixSum - $targetSum];
}
$ans = $countValue
+ $this->countPaths($node->left, $count, $prefixSum, $targetSum)
+ $this->countPaths($node->right, $count, $prefixSum, $targetSum);
$prefixSum -= $node->val;
$count[$prefixSum]--;
return $ans;
}
/**
* @param TreeNode $root
* @param Integer $targetSum
* @return Integer
*/
public function pathSum($root, $targetSum) {
$count = [];
return $this->countPaths($root, $count, 0, $targetSum);
}
}