Easy
Given an array nums
of size n
, return the majority element.
The majority element is the element that appears more than ⌊n / 2⌋
times. You may assume that the majority element always exists in the array.
Example 1:
Input: nums = [3,2,3]
Output: 3
Example 2:
Input: nums = [2,2,1,1,1,2,2]
Output: 2
Constraints:
n == nums.length
1 <= n <= 5 * 104
-231 <= nums[i] <= 231 - 1
Follow-up: Could you solve the problem in linear time and in O(1)
space?
class Solution {
/**
* @param Integer[] $nums
* @return Integer
*/
public function majorityElement($nums) {
$search = array_count_values($nums);
$count = count($nums) / 2;
foreach ($search as $key => $value) {
if ($value > $count) {
return $key;
}
}
}
}