Medium
Given a linked list, swap every two adjacent nodes and return its head. You must solve the problem without modifying the values in the list’s nodes (i.e., only nodes themselves may be changed.)
Example 1:
Input: head = [1,2,3,4]
Output: [2,1,4,3]
Example 2:
Input: head = []
Output: []
Example 3:
Input: head = [1]
Output: [1]
Constraints:
[0, 100]
.0 <= Node.val <= 100
use leetcode\com_github_leetcode\ListNode;
/**
* Definition for a singly-linked list.
* class ListNode {
* public $val = 0;
* public $next = null;
* function __construct($val = 0, $next = null) {
* $this->val = $val;
* $this->next = $next;
* }
* }
*/
class Solution {
/**
* @param ListNode $head
* @return ListNode
*/
public function swapPairs($head) {
$output = new ListNode(0);
$output->next = $head;
$point = $output;
while ($point->next != null && $point->next->next != null) {
$point1 = $point->next;
$point2 = $point->next->next;
$point->next = $point2;
$point1->next = $point2->next;
$point2->next = $point1;
$point = $point1;
}
return $output->next;
}
}