Medium
Given an array of integers temperatures represents the daily temperatures, return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0 instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 10530 <= temperatures[i] <= 100class Solution {
    fun dailyTemperatures(temperatures: IntArray): IntArray {
        val sol = IntArray(temperatures.size)
        sol[temperatures.size - 1] = 0
        for (i in sol.size - 2 downTo 0) {
            var j = i + 1
            while (j <= sol.size) {
                if (temperatures[i] < temperatures[j]) {
                    sol[i] = j - i
                    break
                } else {
                    if (sol[j] == 0) {
                        break
                    }
                    j = j + sol[j]
                }
            }
        }
        return sol
    }
}