Medium
A linked list of length n
is given such that each node contains an additional random pointer, which could point to any node in the list, or null
.
Construct a deep copy of the list. The deep copy should consist of exactly n
brand new nodes, where each new node has its value set to the value of its corresponding original node. Both the next
and random
pointer of the new nodes should point to new nodes in the copied list such that the pointers in the original list and copied list represent the same list state. None of the pointers in the new list should point to nodes in the original list.
For example, if there are two nodes X
and Y
in the original list, where X.random --> Y
, then for the corresponding two nodes x
and y
in the copied list, x.random --> y
.
Return the head of the copied linked list.
The linked list is represented in the input/output as a list of n
nodes. Each node is represented as a pair of [val, random_index]
where:
val
: an integer representing Node.val
random_index
: the index of the node (range from 0
to n-1
) that the random
pointer points to, or null
if it does not point to any node.Your code will only be given the head
of the original linked list.
Example 1:
Input: head = [[7,null],[13,0],[11,4],[10,2],[1,0]]
Output: [[7,null],[13,0],[11,4],[10,2],[1,0]]
Example 2:
Input: head = [[1,1],[2,1]]
Output: [[1,1],[2,1]]
Example 3:
Input: head = [[3,null],[3,0],[3,null]]
Output: [[3,null],[3,0],[3,null]]
Example 4:
Input: head = []
Output: []
Explanation: The given linked list is empty (null pointer), so return null.
Constraints:
0 <= n <= 1000
-10000 <= Node.val <= 10000
Node.random
is null
or is pointing to some node in the linked list.import com_github_leetcode.random.Node
/*
* Example:
* var ti = Node(5)
* var v = ti.`val`
* Definition for a Node.
* class Node(var `val`: Int) {
* var next: Node? = null
* var random: Node? = null
* }
*/
class Solution {
fun copyRandomList(head: Node?): Node? {
if (head == null) {
return null
}
// first pass to have a clone node point to the next node. ie A->B becomes A->clonedNode->B
var curr: Node? = head
while (curr != null) {
val clonedNode = Node(curr.`val`)
clonedNode.next = curr.next
curr.next = clonedNode
curr = clonedNode.next
}
curr = head
// second pass to make the cloned node's random pointer point to the orginal node's randome
// pointer.
// ie. A's random pointer becomes ClonedNode's random pointer
while (curr != null) {
if (curr.random != null) {
curr.next?.random = curr.random!!.next
} else {
curr.next?.random = null
}
curr = curr.next?.next
}
curr = head
// third pass to restore the links and return the head of the cloned nodes' list.
var newHead: Node? = null
while (curr != null) {
var clonedNode: Node
if (newHead == null) {
clonedNode = curr.next!!
newHead = clonedNode
} else {
clonedNode = curr.next!!
}
curr.next = clonedNode.next
if (curr.next != null) {
clonedNode.next = curr.next!!.next
} else {
clonedNode.next = null
}
curr = curr.next
}
return newHead
}
}