Medium
Given an array of integers temperatures
represents the daily temperatures, return an array answer
such that answer[i]
is the number of days you have to wait after the ith
day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0
instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 105
30 <= temperatures[i] <= 100
/**
* @param {number[]} temperatures
* @return {number[]}
*/
var dailyTemperatures = function(temperatures) {
const sol = new Array(temperatures.length).fill(0)
sol[temperatures.length - 1] = 0
for (let i = temperatures.length - 2; i >= 0; i--) {
let j = i + 1
while (j < temperatures.length) {
if (temperatures[i] < temperatures[j]) {
sol[i] = j - i
break
} else {
if (sol[j] === 0) {
break
}
j += sol[j]
}
}
}
return sol
};
export { dailyTemperatures }