Medium
Given an array of integers temperatures represents the daily temperatures, return an array answer such that answer[i] is the number of days you have to wait after the ith day to get a warmer temperature. If there is no future day for which this is possible, keep answer[i] == 0 instead.
Example 1:
Input: temperatures = [73,74,75,71,69,72,76,73]
Output: [1,1,4,2,1,1,0,0]
Example 2:
Input: temperatures = [30,40,50,60]
Output: [1,1,1,0]
Example 3:
Input: temperatures = [30,60,90]
Output: [1,1,0]
Constraints:
1 <= temperatures.length <= 10530 <= temperatures[i] <= 100/**
 * @param {number[]} temperatures
 * @return {number[]}
 */
var dailyTemperatures = function(temperatures) {
    const sol = new Array(temperatures.length).fill(0)
    sol[temperatures.length - 1] = 0
    for (let i = temperatures.length - 2; i >= 0; i--) {
        let j = i + 1
        while (j < temperatures.length) {
            if (temperatures[i] < temperatures[j]) {
                sol[i] = j - i
                break
            } else {
                if (sol[j] === 0) {
                    break
                }
                j += sol[j]
            }
        }
    }
    return sol
};
export { dailyTemperatures }