Medium
Given an integer array nums
and an integer k
, return the kth
largest element in the array.
Note that it is the kth
largest element in the sorted order, not the kth
distinct element.
You must solve it in O(n)
time complexity.
Example 1:
Input: nums = [3,2,1,5,6,4], k = 2
Output: 5
Example 2:
Input: nums = [3,2,3,1,2,4,5,5,6], k = 4
Output: 4
Constraints:
1 <= k <= nums.length <= 105
-104 <= nums[i] <= 104
/**
* @param {number[]} nums
* @param {number} k
* @return {number}
*/
var findKthLargest = function(nums, k) {
const min = Math.min(...nums)
const max = Math.max(...nums)
const dp = new Array(max - min + 1).fill(0)
for (let num of nums) {
dp[num - min]++
}
for (let i = dp.length-1; i >= 0; i--) {
k -= dp[i]
if (k <= 0) return i + min
}
};
export { findKthLargest }