Easy
Given a non-empty array of integers nums
, every element appears twice except for one. Find that single one.
You must implement a solution with a linear runtime complexity and use only constant extra space.
Example 1:
Input: nums = [2,2,1]
Output: 1
Example 2:
Input: nums = [4,1,2,1,2]
Output: 4
Example 3:
Input: nums = [1]
Output: 1
Constraints:
1 <= nums.length <= 3 * 104
-3 * 104 <= nums[i] <= 3 * 104
/**
* @param {number[]} nums
* @return {number}
*/
var singleNumber = function(nums) {
let res = 0
for (const num of nums) {
res ^= num
}
return res
};
export { singleNumber }