LeetCode-in-All
121. Best Time to Buy and Sell Stock
Easy
You are given an array prices where prices[i] is the price of a given stock on the ith day.
You want to maximize your profit by choosing a single day to buy one stock and choosing a different day in the future to sell that stock.
Return the maximum profit you can achieve from this transaction. If you cannot achieve any profit, return 0.
Example 1:
Input: prices = [7,1,5,3,6,4]
Output: 5
Explanation: Buy on day 2 (price = 1) and sell on day 5 (price = 6), profit = 6-1 = 5.
Note that buying on day 2 and selling on day 1 is not allowed because you must buy before you sell.
Example 2:
Input: prices = [7,6,4,3,1]
Output: 0
Explanation: In this case, no transactions are done and the max profit = 0.
Constraints:
1 <= prices.length <= 1050 <= prices[i] <= 104
Solution
/**
* @param {number[]} prices
* @return {number}
*/
var maxProfit = function(prices) {
let maxProfit = 0
let min = prices[0]
for (let i = 1; i < prices.length; i++) {
if (prices[i] > min) {
maxProfit = Math.max(maxProfit, prices[i] - min)
} else {
min = prices[i]
}
}
return maxProfit
};
export { maxProfit }