Medium
Given two strings text1
and text2
, return the length of their longest common subsequence. If there is no common subsequence, return 0
.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
"ace"
is a subsequence of "abcde"
.A common subsequence of two strings is a subsequence that is common to both strings.
Example 1:
Input: text1 = “abcde”, text2 = “ace”
Output: 3
Explanation: The longest common subsequence is “ace” and its length is 3.
Example 2:
Input: text1 = “abc”, text2 = “abc”
Output: 3
Explanation: The longest common subsequence is “abc” and its length is 3.
Example 3:
Input: text1 = “abc”, text2 = “def”
Output: 0
Explanation: There is no such common subsequence, so the result is 0.
Constraints:
1 <= text1.length, text2.length <= 1000
text1
and text2
consist of only lowercase English characters.func longestCommonSubsequence(text1 string, text2 string) int {
n := len(text1)
m := len(text2)
dp := make([][]int, n+1)
for i := range dp {
dp[i] = make([]int, m+1)
}
for i := 1; i <= n; i++ {
for j := 1; j <= m; j++ {
if text1[i-1] == text2[j-1] {
dp[i][j] = dp[i-1][j-1] + 1
} else {
dp[i][j] = max(dp[i-1][j], dp[i][j-1])
}
}
}
return dp[n][m]
}
func max(a, b int) int {
if a > b {
return a
}
return b
}