Medium
Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n) time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Constraints:
0 <= nums.length <= 105-109 <= nums[i] <= 109import "sort"
func longestConsecutive(nums []int) int {
	if len(nums) == 0 {
		return 0
	}
	sort.Ints(nums)
	max := -1 << 31 // Integer.MIN_VALUE in Go
	thsMax := 1
	for i := 0; i < len(nums)-1; i++ {
		if nums[i+1] == nums[i]+1 {
			thsMax++
			continue
		}
		if nums[i+1] == nums[i] {
			continue
		}
		// Start of a new Sequence
		if thsMax > max {
			max = thsMax
		}
		thsMax = 1
	}
	if thsMax > max {
		max = thsMax
	}
	return max
}