Medium
Given an unsorted array of integers nums
, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n)
time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]
. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Constraints:
0 <= nums.length <= 105
-109 <= nums[i] <= 109
import "sort"
func longestConsecutive(nums []int) int {
if len(nums) == 0 {
return 0
}
sort.Ints(nums)
max := -1 << 31 // Integer.MIN_VALUE in Go
thsMax := 1
for i := 0; i < len(nums)-1; i++ {
if nums[i+1] == nums[i]+1 {
thsMax++
continue
}
if nums[i+1] == nums[i] {
continue
}
// Start of a new Sequence
if thsMax > max {
max = thsMax
}
thsMax = 1
}
if thsMax > max {
max = thsMax
}
return max
}