Easy
Given an integer x
, return true
if x
is palindrome integer.
An integer is a palindrome when it reads the same backward as forward. For example, 121
is palindrome while 123
is not.
Example 1:
Input: x = 121
Output: true
Example 2:
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Example 4:
Input: x = -101
Output: false
Constraints:
-231 <= x <= 231 - 1
Follow up: Could you solve it without converting the integer to a string?
func isPalindrome(x int) bool {
if x < 10 {
return x >= 0
}
if x%10 == 0 {
return false
}
a, b := x, 0
for a > b {
a, b = a/10, b*10+a%10
}
return a == b || a == b/10
}