Medium
Given an integer array nums
and an integer k
, return the kth
largest element in the array.
Note that it is the kth
largest element in the sorted order, not the kth
distinct element.
You must solve it in O(n)
time complexity.
Example 1:
Input: nums = [3,2,1,5,6,4], k = 2
Output: 5
Example 2:
Input: nums = [3,2,3,1,2,4,5,5,6], k = 4
Output: 4
Constraints:
1 <= k <= nums.length <= 105
-104 <= nums[i] <= 104
-spec find_kth_largest(Nums :: [integer()], K :: integer()) -> integer().
find_kth_largest(Nums, K) ->
Q = gb_sets:new(),
FinalQ = lists:foldl(fun({N, I}, AccQ) ->
case gb_sets:is_element({N, I}, AccQ) of
true -> AccQ;
false ->
case gb_sets:size(AccQ) < K of
true ->
gb_sets:insert({N, I}, AccQ);
false ->
{Smallest, TempQ} = gb_sets:take_smallest(AccQ),
gb_sets:insert(max(Smallest, {N, I}), TempQ)
end
end
end, Q, lists:zip(Nums, lists:seq(1, length(Nums)))),
element(1, gb_sets:smallest(FinalQ)).
% Helper function to find the maximum of two tuples based on their first element.
max({N1, I1}, {N2, I2}) when N1 >= N2 -> {N1, I1};
max(_, {N2, I2}) -> {N2, I2}.