LeetCode-in-All

437. Path Sum III

Medium

Given the root of a binary tree and an integer targetSum, return the number of paths where the sum of the values along the path equals targetSum.

The path does not need to start or end at the root or a leaf, but it must go downwards (i.e., traveling only from parent nodes to child nodes).

Example 1:

Input: root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8

Output: 3

Explanation: The paths that sum to 8 are shown.

Example 2:

Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22

Output: 3

Constraints:

Solution

# Definition for a binary tree node.
#
# defmodule TreeNode do
#   @type t :: %__MODULE__{
#           val: integer,
#           left: TreeNode.t() | nil,
#           right: TreeNode.t() | nil
#         }
#   defstruct val: 0, left: nil, right: nil
# end

defmodule Solution do
  def path_sum(nil, _, _), do: 0
  @spec path_sum(root :: TreeNode.t | nil, target_sum :: integer, partial_sums :: [integer]) :: integer
  def path_sum(root, target_sum, partial_sums \\ []) do
    new_partials = [root.val | Enum.map(partial_sums, &(&1 + root.val))]
    equal_path = Enum.count(Enum.filter(new_partials, &(&1 == target_sum)))
    equal_path + 
      path_sum(root.left, target_sum, new_partials) + 
      path_sum(root.right, target_sum, new_partials)
  end
end