LeetCode-in-All
1143. Longest Common Subsequence
Medium
Given two strings text1 and text2, return the length of their longest common subsequence. If there is no common subsequence, return 0.
A subsequence of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters.
- For example,
"ace"is a subsequence of"abcde".
A common subsequence of two strings is a subsequence that is common to both strings.
Example 1:
Input: text1 = “abcde”, text2 = “ace”
Output: 3
Explanation: The longest common subsequence is “ace” and its length is 3.
Example 2:
Input: text1 = “abc”, text2 = “abc”
Output: 3
Explanation: The longest common subsequence is “abc” and its length is 3.
Example 3:
Input: text1 = “abc”, text2 = “def”
Output: 0
Explanation: There is no such common subsequence, so the result is 0.
Constraints:
1 <= text1.length, text2.length <= 1000text1andtext2consist of only lowercase English characters.
Solution
#include <vector>
#include <string>
#include <algorithm>
class Solution {
public:
int longestCommonSubsequence(const std::string& text1, const std::string& text2) {
int n = text1.size();
int m = text2.size();
std::vector<std::vector<int>> dp(n + 1, std::vector<int>(m + 1, 0));
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= m; ++j) {
if (text1[i - 1] == text2[j - 1]) {
dp[i][j] = dp[i - 1][j - 1] + 1;
} else {
dp[i][j] = std::max(dp[i - 1][j], dp[i][j - 1]);
}
}
}
return dp[n][m];
}
};