Medium
Given an encoded string, return its decoded string.
The encoding rule is: k[encoded_string]
, where the encoded_string
inside the square brackets is being repeated exactly k
times. Note that k
is guaranteed to be a positive integer.
You may assume that the input string is always valid; No extra white spaces, square brackets are well-formed, etc.
Furthermore, you may assume that the original data does not contain any digits and that digits are only for those repeat numbers, k
. For example, there won’t be input like 3a
or 2[4]
.
Example 1:
Input: s = “3[a]2[bc]”
Output: “aaabcbc”
Example 2:
Input: s = “3[a2[c]]”
Output: “accaccacc”
Example 3:
Input: s = “2[abc]3[cd]ef”
Output: “abcabccdcdcdef”
Example 4:
Input: s = “abc3[cd]xyz”
Output: “abccdcdcdxyz”
Constraints:
1 <= s.length <= 30
s
consists of lowercase English letters, digits, and square brackets '[]'
.s
is guaranteed to be a valid input.s
are in the range [1, 300]
.#include <string>
#include <cctype>
using namespace std;
class Solution {
private:
int i = 0;
public:
string decodeString(const string& s) {
int count = 0;
string result;
while (i < s.length()) {
char c = s[i];
++i;
if (isalpha(c)) {
result += c;
} else if (isdigit(c)) {
count = count * 10 + (c - '0');
} else if (c == ']') {
break;
} else if (c == '[') {
// sub problem
string repeat = decodeString(s);
while (count > 0) {
result += repeat;
--count;
}
}
}
return result;
}
};