Medium
Given n
non-negative integers a1, a2, ..., an
, where each represents a point at coordinate (i, ai)
. n
vertical lines are drawn such that the two endpoints of the line i
is at (i, ai)
and (i, 0)
. Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.
Notice that you may not slant the container.
Example 1:
Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example 2:
Input: height = [1,1]
Output: 1
Example 3:
Input: height = [4,3,2,1,4]
Output: 16
Example 4:
Input: height = [1,2,1]
Output: 2
Constraints:
n == height.length
2 <= n <= 105
0 <= height[i] <= 104
#include <vector>
using namespace std;
class Solution {
public:
int maxArea(vector<int>& height) {
int maxArea = 0;
int left = 0;
int right = height.size() - 1;
while (left < right) {
int h = min(height[left], height[right]);
maxArea = max(maxArea, h * (right - left));
if (height[left] < height[right]) {
left++;
} else {
right--;
}
}
return maxArea;
}
};