Medium
The string "PAYPALISHIRING" is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)
P A H N A P L S I I G Y I R
And then read line by line: "PAHNAPLSIIGYIR"
Write the code that will take a string and make this conversion given a number of rows:
string convert(string s, int numRows);
Example 1:
Input: s = “PAYPALISHIRING”, numRows = 3
Output: “PAHNAPLSIIGYIR”
Example 2:
Input: s = “PAYPALISHIRING”, numRows = 4
Output: “PINALSIGYAHRPI”
Explanation: P I N A L S I G Y A H R P I
Example 3:
Input: s = “A”, numRows = 1
Output: “A”
Constraints:
1 <= s.length <= 1000s consists of English letters (lower-case and upper-case), ',' and '.'.1 <= numRows <= 1000#include <string>
#include <vector>
class Solution {
public:
    std::string convert(std::string s, int numRows) {
        int sLen = s.length();
        if (numRows == 1) {
            return s;
        }
        int maxDist = numRows * 2 - 2;
        std::string buf;
        buf.reserve(sLen);
        for (int i = 0; i < numRows; i++) {
            int index = i;
            if (i == 0 || i == numRows - 1) {
                while (index < sLen) {
                    buf += s[index];
                    index += maxDist;
                }
            } else {
                while (index < sLen) {
                    buf += s[index];
                    index += maxDist - i * 2;
                    if (index >= sLen) {
                        break;
                    }
                    buf += s[index];
                    index += i * 2;
                }
            }
        }
        return buf;
    }
};