LeetCode-in-All

543. Diameter of Binary Tree

Easy

Given the root of a binary tree, return the length of the diameter of the tree.

The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.

The length of a path between two nodes is represented by the number of edges between them.

Example 1:

Input: root = [1,2,3,4,5]

Output: 3

Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3].

Example 2:

Input: root = [1,2]

Output: 1

Constraints:

Solution

#include <stdio.h>
#include <stdlib.h>

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     struct TreeNode *left;
 *     struct TreeNode *right;
 * };
 */
// Global variable to store the maximum diameter
int diameter;

// Helper function to calculate the diameter of the binary tree
int diameterOfBinaryTreeUtil(struct TreeNode* root) {
    if (root == NULL) {
        return 0;
    }
    
    // Calculate left and right path lengths
    int leftLength = root->left ? 1 + diameterOfBinaryTreeUtil(root->left) : 0;
    int rightLength = root->right ? 1 + diameterOfBinaryTreeUtil(root->right) : 0;
    
    // Update the diameter if the path through this node is larger
    if (leftLength + rightLength > diameter) {
        diameter = leftLength + rightLength;
    }
    
    // Return the maximum path length from this node
    return leftLength > rightLength ? leftLength : rightLength;
}

// Main function to find the diameter of the binary tree
int diameterOfBinaryTree(struct TreeNode* root) {
    diameter = 0; // Initialize diameter to 0
    diameterOfBinaryTreeUtil(root); // Calculate diameter using the utility function
    return diameter;
}