Easy
Given an integer x
, return true
if x
is palindrome integer.
An integer is a palindrome when it reads the same backward as forward. For example, 121
is palindrome while 123
is not.
Example 1:
Input: x = 121
Output: true
Example 2:
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Example 4:
Input: x = -101
Output: false
Constraints:
-231 <= x <= 231 - 1
Follow up: Could you solve it without converting the integer to a string?
#include <stdio.h>
#include <stdbool.h>
bool isPalindrome(int x) {
if (x < 0) {
return false;
}
int rev = 0;
int localX = x;
while (localX > 0) {
// Check for potential overflow
if (rev > (2147483647 / 10)) {
return false; // This would overflow in 32-bit int
}
rev = rev * 10 + (localX % 10);
localX /= 10;
}
return rev == x;
}