Easy
Given an integer x, return true if x is palindrome integer.
An integer is a palindrome when it reads the same backward as forward. For example, 121 is palindrome while 123 is not.
Example 1:
Input: x = 121
Output: true
Example 2:
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Example 4:
Input: x = -101
Output: false
Constraints:
-231 <= x <= 231 - 1Follow up: Could you solve it without converting the integer to a string?
#include <stdio.h>
#include <stdbool.h>
bool isPalindrome(int x) {
    if (x < 0) {
        return false;
    }
    int rev = 0;
    int localX = x;
    while (localX > 0) {
        // Check for potential overflow
        if (rev > (2147483647 / 10)) {
            return false; // This would overflow in 32-bit int
        }
        
        rev = rev * 10 + (localX % 10);
        localX /= 10;
    }
    return rev == x;
}