Medium
Given a signed 32-bit integer x
, return x
with its digits reversed. If reversing x
causes the value to go outside the signed 32-bit integer range [-231, 231 - 1]
, then return 0
.
Assume the environment does not allow you to store 64-bit integers (signed or unsigned).
Example 1:
Input: x = 123
Output: 321
Example 2:
Input: x = -123
Output: -321
Example 3:
Input: x = 120
Output: 21
Example 4:
Input: x = 0
Output: 0
Constraints:
-231 <= x <= 231 - 1
int reverse(int x) {
long rev = 0;
while (x != 0) {
rev = (rev * 10) + (x % 10);
x /= 10;
}
// Check for overflow
if (rev > INT_MAX || rev < INT_MIN) {
return 0;
}
return (int)rev;
}